10x^2-6x=16

Solution for 10x^2-6x=16 equation:

10x^2-6x=16

We move all terms to the left:

10x^2-6x-(16)=0

a = 10; b = -6; c = -16;
Δ = b2-4ac
Δ = -62-4·10·(-16)
Δ = 676
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{676}=26$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-6)-26}{2*10}=\frac{-20}{20}
=-1
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-6)+26}{2*10}=\frac{32}{20}
=1+3/5
$